You are given several identical resistances each of value
and each capable of carrying a maximum current of one ampere. It is required to make a suitable combination of these resistances of 5
which can carry a current of 4 ampere. The minimum number of resistances of the type
that will be required for this job is
Text Solution
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To carry a current of 4 ampere, we need four paths, each carrying a current of one ampere. Let
be the resistance of each path. These are connected in parallel. Hence their equivalent resistance will be
. According to the given problem
or 
For this purpose two resistances should be connected. There are four such combinations. Hence, the total number of resistance

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